-2x^2-12x+9=0

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Solution for -2x^2-12x+9=0 equation:



-2x^2-12x+9=0
a = -2; b = -12; c = +9;
Δ = b2-4ac
Δ = -122-4·(-2)·9
Δ = 216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{216}=\sqrt{36*6}=\sqrt{36}*\sqrt{6}=6\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-6\sqrt{6}}{2*-2}=\frac{12-6\sqrt{6}}{-4} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+6\sqrt{6}}{2*-2}=\frac{12+6\sqrt{6}}{-4} $

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